Sets Chapter-1 NCERT Solutions Class 11 Math Exercise 1.3 PDF Free Download

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NCERT Question 1. Make correct statements by filling in the symbols ⊂ or ⊄ in the blank spaces:
(i) {2, 3, 4} . . . {1, 2, 3, 4, 5}
(ii) {a, b, c} . . . {b, c, d}
(iii) {x : x is a student of Class XI of your school}. . .{x : x student of your school}
(iv) {x: x is a circle in the plane} . . .{x: x is a circle in the same plane with radius 1 unit}
(v) {x : x is a triangle in a plane} . . . {x : x is a rectangle in the plane}
(vi) {x : x is an equilateral triangle in a plane} . . . {x : x is a triangle in the same plane}
(vii) {x : x is an even natural number} . . . {x : x is an integer}

Solution:

(i) {2, 3, 4} ⊂ {1, 2, 3, 4,5}

(ii) {a, b, c} ⊄ {b, c, d}

(iii) {x : x is a student of Class XI of your school} ⊂ {x : x student of your school}

(iv) {x : x is a circle in the plane} ⊄ {x : x is a circle in the same plane with radius 1 unit}

(v) {x : x is a triangle in a plane} ⊄ {x : x is a rectangle in the plane}

(vi) {x : x is an equilateral triangle in a plane} ⊂ {x : x is a triangle in the same plane}

(vii) {x : x is an even natural number} ⊂ {x : x is an integer}

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NCERT Question 2. Examine whether the following statements are true or false:
(i) {a, b} ⊄ {b, c, a}
(ii) {a, e} ⊂ {x : x is a vowel in the English alphabet}
(iii) {1, 2, 3} ⊂ {1, 3, 5}
(iv) {a} ⊂ {a, b, c}
(v) {a} ∈ {a, b, c}
(vi) {x : x is an even natural number less than 6} ⊂ {x : x is a natural number which divides 36} 

Solution:

(i) False. Each element of {a, b} is an element of {b, c, a}.  

(ii) True. Since a, e are two vowels of the English alphabet.  

(iii) False. 2 is subset of {1, 2, 3} but not subset of {1, 3, 5}

(iv) True. Each element of {a} is also an element of {a, b. c} .  

(v) False. Elements of {a, b, c} are a, b, c. Hence, {a} ⊂ {a, b, c}  

(vi) True

      {x : x is an even natural number less than 6} = {2, 4}

      {x: x is a natural number which divides 36} = {1, 2, 3, 4, 6, 9, 12, 18, 36}

      Hence, {2, 4} ⊂ {1, 2, 3, 4, 6, 9, 12, 18, 36}

Sets NCERT Solutions by Anand Classes Class 11 Maths Exercise 1.3 PDF Free Download


NCERT Question 3. Let A = {1, 2, {3, 4}, 5}. Which of the following statements are incorrect and why?
(i) {3, 4} ⊂ A      
(ii) {3, 4} ∈ A      
(iii) {{3, 4}} ⊂ A      
(iv) 1 ∈ A      
(v) 1 ⊂ A      
(vi) {1, 2, 5} ⊂ A
(vii) {1, 2, 5} ∈ A      
(viii) {1, 2, 3} ⊂ A      
(ix) ∅ ∈ A      
(x) ∅ ⊂ A      
(xi) {∅} ⊂ A

Solution:

Given A= {1, 2, {3, 4}, 5} 

(i) {3, 4} ⊂ A is incorrect. Here 3 ∈ {3, 4}, where 3 ∉ A.  

(ii) {3, 4} ∈ A is correct. {3, 4} is an element of A.  

(iii) {{3, 4}} ⊂ A is correct. {3, 4} ∈ {{3, 4}} and {3, 4} ∈ A.  

(iv) 1 ∈ A is correct. 1 is an element of A.  

(v) 1 ⊂ A is incorrect. An element of a set can never be a subset of itself.  

(vi) {1, 2, 5} ⊂ A is correct. Each element of {1, 2, 5} is also an element of A. 

(vii) {1, 2, 5} ∈ A is incorrect. { 1, 2, 5 } is not an element of A.  

(viii) {1, 2, 3} ⊂ A is incorrect. 3 ∈ {1, 2, 3}; where, 3 ∉ A.  

(ix) ∅ ∈ A is incorrect. ∅ is not an element of A.  

(x) ∅ ⊂ A is correct. ∅ is a subset of every set.  

(xi) {∅} ⊂ A is incorrect. {∅} is not present in A. 

Step-by-step, easy-to-understand solutions by Anand Classes based on the latest NCERT syllabus for effective exam preparation.


NCERT Question 4. Write down all the subsets of the following sets
(i) {a}      (ii) {a, b}      (iii) {1, 2, 3}      (iv) ∅

Solution:

(i) Subsets of {a} are ∅ and {a}.  

(ii) Subsets of {a, b} are {a}, {b}, and {a, b}.  

(iii) Subsets of {1, 2, 3} are ∅, {1}, {2}, {3}, {1, 2}, {2, 3}, {1, 3}, and {1, 2, 3}.  

(iv) Only subset of ∅ is ∅. 

Class 11 Maths Sets Chapter Exercise 1.3 Solutions by Anand Classes


NCERT Question 5. Write the following as intervals:
(i) {x : x ∈ R, – 4 < x ≤ 6}           (ii) {x : x ∈ R, – 12 < x < –10}
(iii) {x : x ∈ R, 0 ≤ x < 7}            (iv) {x : x ∈ R, 3 ≤ x ≤ 4}

Solution:

(i) {x : x ∈ R, – 4 < x ≤ 6} = (-4, 6]

(ii) {x : x ∈ R, – 12 < x < –10} = (-12, -10)

(iii) {x : x ∈ R, 0 ≤ x < 7} = [0, 7)

(iv) {x : x ∈ R, 3 ≤ x ≤ 4} = [3, 4]

Class 11 Sets Exercise 1.3 PDF Download, NCERT Class 11 Maths Chapter 1 Solutions


NCERT Question 6. Write the following intervals in set-builder form :
(i) (– 3, 0)         (ii) [6, 12]         (iii) (6, 12]         (iv) [–23, 5)

Solution:

(i) (– 3, 0) = {x : x ∈ R, -3 < x < 0}

(ii) [6, 12] = {x : x ∈ R, 6 ≤ x ≤ 12}

(iii) (6, 12] = {x : x ∈ R, 6 < x ≤ 12}

(iv) [–23, 5) = {x : x ∈ R, -23 ≤ x < 5}

Class 11 Maths Chapter 1 Sets Exercise 1.3 Solutions by Anand Classes.


NCERT Question 7. What universal set(s) would you propose for each of the following :
(i) The set of right triangles
(ii) The set of isosceles triangles.

Solution:

(i) The universal set for the set of right triangles is the set of triangles or the set of polygons.

(ii) The universal set for the set of isosceles triangles is the set of triangles or the set of polygons or the set of two-dimensional figures.


NCERT Question 8. Given the sets A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}, which of the following may be considered as universal set (s) for all the three sets A, B and C
(i) {0, 1, 2, 3, 4, 5, 6}
(ii) ∅
(iii) {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(iv) {1, 2, 3, 4, 5, 6, 7, 8} 

Solution:

(i) A ⊂ {0, 1, 2, 3, 4, 5, 6}

    B ⊂ {0, 1, 2, 3, 4, 5, 6}

    But, C ⊄ {0, 1, 2, 3, 4, 5, 6}

    Hence, the set {0, 1, 2, 3, 4, 5, 6} cannot be the universal set for the sets A, B, and C.

(ii) A ⊄ ∅, B ⊄ ∅, C ⊄ ∅

     Hence, ∅ cannot be the universal set for the sets A, B, and C.

(iii) A ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

      B ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

      C ⊂ {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

      Hence, the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10} is the universal set for the sets A, B, and C.

(iv) A ⊂ {1, 2, 3, 4, 5, 6, 7, 8} 

      B ⊂ {1, 2, 3, 4, 5, 6, 7, 8} 

      But, C ⊄ {1, 2, 3, 4, 5, 6, 7, 8} 

      Hence, the set {1, 2, 3, 4, 5, 6, 7, 8} cannot be the universal set for the sets A, B, and C.


NCERT Question 9. How many elements has P(A), if A = ∅? 

Solution:

For a set A with n(A) = m, then it can be shown that

Number of elements of P(A) = n[P(A)] = 2m

If A = ∅, we get n (A) = 0 

So, n[P(A)] = 2° = 1  

Therefore, P(A) has one element. 

⬅️ NCERT Solutions Exercise 1.4 Exercise 1.2 NCERT Solutions ➡️

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