Integration by Substitution Formula | Sample Problems | Class 12 Math Notes Study Material Download Free PDF

โญโญโญโญโœฉ (4.9/5 from 143 reviews)

The process of finding the anti-derivative of a function is the inverse process of differentiation i.e. finding integral is the inverse process of differentiation. Integration can be used to find the area or volume of a function with or without certain limits or boundaries 

It is shown as

โˆซg(x)dx = G(x) + C 

Explanation:

It means integral of function โ€œg(x)โ€ with respective โ€œxโ€

G(x) represents the anti-derivative and can also state that the derivative of G(x) w.r.t x is g(x)

g(x) is the integrand on which integration is performed

dx is integrating agent

C is called integration constant

With a diagram

Integration by substitution formula | sample problems | class 12 math notes study material download free pdf

Lets us say we need to find an Area Under a Curve let the function be f(x)

The area can be found by integrating the function between the boundaries a and b

let us say โˆซ f(x)dx = F(x)

the area under the curve given as F(b)-F(a) given โ€˜bโ€™ as the upper limit and โ€˜aโ€™ as the lower limit

Integration for some standard function

โˆซ a dx = ax+ C ;Where a is constant

โˆซ xn dx = ((xn+1)/(n+1))+C ; nโ‰ 1.

โˆซ sin x dx = โ€“ cos x + C.

โˆซ cos x dx = sin x + C.

โˆซ sec2 x dx = tan x + C.

Integration by Substitution

Integration of a few standard functions is given, but to find out the integrals of various functions apart from basic functions we apply different methods to bring the functions to basic functions format so that integration can be performed. One of those methods is the Integration by substitution method.

The chain rule used to perform differentiation is applied in a reverse format which is why this method is also called as reverse chain rule or u-substitution method.

In this method, the integral function is transformed into another format i.e. into the simplest form by replacing or substituting independent variables like โ€œxโ€ with others 

Example: โˆซ(3x2-5)(6x)dx

Solution:

Let us assume 3x2-5=t

performing the differentiation on both sides

6x.dx=dt

Now substitute  3x2-5 as โ€œtโ€  and 6x.dx as dt in the given we get

โˆซt.dt 

w.k.t( i.e. We Know That)

โˆซ xn dx = ((xn+1)/(n+1))+C ; n โ‰  1

applying this standard formula we get (t2)/2+c

replacing t with  3x2-5

The answer is  ((3x2-5)2)/2

When to apply the Integration by Substitution method

To find integral by using this method it needs to be present in a specific format and the general form is given as

โˆซ f(g(x)).g'(x).dx = f(t).dt

where g(x)=t

g'(x).dx=dt

โˆซf(t).dt=F(t)+c=F(g(x))+c

We substitute g(x) with t and convert it into a simple or standard function format and perform the integration and finally replace t with g(x)

Sample Problems

Question 1: โˆซtan x dx

Solution:

โˆซ(sin x/cos x).dx

let us assume cos x=t

performing the differentiation on both sides

-sin x.dx=dt

=-โˆซdt/t

w.k.tโˆซ1/t=ln |t| โ€ฆ.(w.k.t. = We Know That )

=-ln |t|

replacing t with cos x

=-ln |cos x| or ln |sec x|

Question 2: โˆซcot x dx

Solution:

โˆซ(cos x/sin x)dx

assume sin x=t

performing the differentiation on both sides

cos x.dx=dt

=โˆซdt/t

w.k.tโˆซ1/t=ln|t|

=ln|t|

replacing t with sin x

=ln |sin x| or -ln |cos x|

Question 3: โˆซsec x dx

Solution:

It can be rewritten as โˆซ(sec x (sec x+tan x))/(sec x+tan x) dx

let us assume secx+tanx=t

performing the differentiation on both sides

(sec x.tan x+sec2 x)dx=dt

sec x(tan x+sec x).dx=dt

=โˆซdt/t

w.k.tโˆซ1/t=ln|t|

=ln|t|

replacing t with secx+tanx

=ln |secx+tanx|

Question 4: โˆซcosec x dx

Solution:

It can be rewritten as 

=โˆซ(cosec x(cosec x+cot x))/(cosec x+cot x) dx

let us assume cosec x+cot x=t

(-cosec x.cot x-cosec2 x)dx=dt

-cosec x(cot x+cosec x)dx=dt

=-โˆซdt/t

w.k.tโˆซ1/t=ln |t|

=ln |t|

replacing t with cosec x +co tx

=ln |cosec x + cot x|

Question 5: โˆซx.sin(8+2x2)dx

Solution:

Assume 8+2x2=t

performing the differentiation on both sides

4xdx=dt

xdx=dt/4

=1/4โˆซsin(t)dt

wkt โˆซ sin x dx = โ€“ cos x + C.

=1/4โˆซsin(t)dt=1/4(-cost)+c

replacing t with 8+2(x^2)

=(-cos(8+2x2))/4+C

Question 6: โˆซ(2w-4)(2w2-8w+10)3.dw

Solution:

Assume 2w2-8w+10=t

performing the differentiation on both sides

(4w-8)dw=dt

(2w-4)dw=dt/2

=1/2(โˆซt3.dt)

โˆซ xn dx = ((xn+1)/(n+1))+C ; nโ‰ 1

=1/2(โˆซt3.dt)=(1/2).(1/4)(t4)+C

replacing t with 2w2-8w+10

=1/8((2w2-8w+10)4)+C

Question 7: โˆซp/(1+5p2).dp

Solution:

Assume 1+5p2=t

performing the differentiation on both sides

10pdp=dt

pdp=dt/10

=1/10(โˆซdt/t)

w.r.t โˆซ1/p=|logp|+C

=1/10(|logt|)+C

replacing t with 1+5p2

=1/10(|log(1+5p2)|)+C

Question 8: โˆซcos(8x + 8) dx 

Solution:

Assume 8x+8=t

performing the differentiation on both sides

8dx=dt

1/8(โˆซcost dt)

w.r.t โˆซ cos x dx = sin x + C.

1/8(โˆซcost dt)=1/8(sint)+C

replacing t with 8x+8

1/8(sin(8x+8))+C

Question 9: โˆซ(3sin x).cos x.dx

Solution:

Assume sin x=t

performing the differentiation on both sides

cos x.dx=dt

=โˆซ(3t)dt

w.r.t โˆซ ax dx = (ax/ln a) + C ; a>0,  aโ‰ 1

=โˆซ(3t)dt=(3t)/ln 3

replacing t with sinx

=(3^sinx)/ln 3

Practice Problems โ€“ Integration by Substitution Formula

Try out the given problems to master the concept of Integration by Substitution :

Q1 : โˆซ [(ln (x))โฟ/x] dx

Q2 : โˆซ [(Sinโปยน(x))ยณ/โˆš(1-xยฒ)] dx

Q3 : โˆซ [2x(e)^(xยฒ)] dx

Q4 : โˆซ [x/โˆš(1+xยฒ)] dx

Q5 : โˆซ Cos(3x)Sin(3x) dx

Q6 : โˆซ [2x/(1+xยฒ)] dx

Q7 : โˆซ [xโˆš(1-xยฒ)] dx

Q8 : โˆซ 2 e^(2x) dx

Q9 : โˆซ (2x + 1)/(xยฒ + x + 1) dx

Q10 : โˆซ [Sin( ln(x)) . (1/x)] dx

Hint for Q3   -> Let u = 3x and Use identity : Sin(2u) = 2 Sin(u) Cos(u) , then let v = 2u.

FAQs on Integration by Substitution

What is integration by substitution?

Integration by substitution is a method used to evaluate integrals. It involves changing the variable of integration to simplify the integral. This technique is analogous to the chain rule for differentiation.

What is the formula for integration by substitution?

The formula for integration by substitution is:

โˆซf(g(x))g'(x) dx = โˆซf(u) du

where , u = g(x)

How do you choose the substitution u?

Choosing the substitution u typically involves identifying a function inside the integral whose derivative is also present in the integral. Often, u is set to be the inner function in a composite function.

What if the integral doesnโ€™t match exactly after substitution?

If the integral doesnโ€™t match exactly after substitution, you may need to manipulate the integral algebraically. For instance, you might factor out constants or split the integral into parts.

Can integration by substitution be used for definite integrals?

Yes, integration by substitution can be used for definite integrals. However, you need to change the limits of integration according to the substitution as :

What are Common Mistakes to Avoid?

  • Forgetting to change the limits of integration when dealing with definite integrals.
  • Not simplifying the integral properly after substitution.
  • Incorrectly differentiating or integrating functions.

Are there any functions that are particularly suited for substitution?

Functions involving compositions such as polynomials within trigonometric, exponential, or logarithmic functions often goes well with substitution method. Identifying an inner function whose derivative is present in the integral is key here.

โฌ…๏ธ Integration by Substitution Formula | Sample Problems | Class 12 Math Notes Study Material Download Free PDF Partial Fraction in Integration – Definition, Formula, Decomposition, Examples | Class 12 Math Notes Study Material Download Free PDF โžก๏ธ

๐Ÿ“š Buy Study Material & Join Our Coaching

For premium study materials specially designed for NDA Exam, visit our official study material portal:
๐Ÿ‘‰ https://publishers.anandclasses.co.in/

For JEE/NEET Notes : Visit https://anandclasses.in/

To enroll in our offline or online coaching programs, visit our coaching center website:
๐Ÿ‘‰ https://anandclasses.co.in/

๐Ÿ“ž Call us directly at: +91-94631-38669

๐Ÿ’ฌ WhatsApp Us Instantly

Need quick assistance or want to inquire about classes and materials?

๐Ÿ“ฒ Click below to chat instantly on WhatsApp:
๐Ÿ‘‰ Chat on WhatsApp

๐ŸŽฅ Watch Video Lectures

Get access to high-quality video lessons, concept explainers, and revision tips by subscribing to our official YouTube channel:
๐Ÿ‘‰ Neeraj Anand Classes โ€“ YouTube Channel

RELATED TOPICS