Empirical Formula Calculation with Related Examples

Empirical Formula

The simplest formula or the empirical formula provides the lowest whole number ratio of atoms existent in a compound. The relative number of atoms of every element in the compound is provided by this formula.

Steps for Determining an Empirical Formula

  • Let’s begin with what’s given in the problem, i.e., the number of grams of each element.
  • We’ll assume that the total mass is 100 grams if percentages are given, so that

Each element’s mass = the given percentage

  • By making use of the molar mass from the periodic table, change the mass of every element to moles.
  • Divide every mole value by the lowest number of moles computed.
  • Round up to the closest whole number.  This is denoted by subscripts in the empirical formula and is the mole ratio of the elements.

Multiply each answer by the same factor to get the lowest whole number multiple, if the number is too far to round off (x.1 ~ x.9).

e.g.  Multiply each solution in the problem by 4 to get 5, if one solution is 1.25.

e.g.  Multiply each solution in the problem by 2 to get 3, if one solution is 1.5.

The molecular formula can be calculated for a compound if the molar mass of the compound is given when the empirical formula is found.  To find the ratio between the molecular formula and the empirical formula. Basically, the mass of the empirical formula can be computed by dividing the molar mass of the compound by it.  Multiply every atom (subscripts) by this ratio to compute the molecular formula.

Solved Examples

Problem 1: A compound contains 88.79% oxygen (O) and 11.19% hydrogen (H). Compute the empirical formula of the compound.

Solution:

  1. Assume 100.0g of substance. We see that the percentage of each element matches the grams of each element

11.19g H

88.79g O

  1. Convert grams of each element to moles

H: (11.19/1.008) = 11.10 mol H atoms [molar mass of H=1.008g/mol]

O: (88.79/16.00) = 5.549 mol O atoms [molar mass of O= 16.00g/mol]

The formula could be articulated as H = 11.10, O = 5.549. However, it’s usual to use the smallest whole number ratio of atoms

  1. By dividing the lowest number alter the numbers to whole numbers.

H =11.10/ 5.549  = 2.000

O = 5.549/ 5.549= 1.000

The simplest ratio of H to O is 2:1

Empirical formula = H2O

Problem 2: A sulfide of iron was formed by combining 1.926g of sulfur(S) with 2.233g of iron (Fe). What is the compound’s empirical formula?

Solution:

  1. As the mass of each element is known, we use them directly
  2. Convert grams of each element to moles

Fe: (2.233g /55.85g) = 0.03998 mol Fe atoms [molar mass of Fe =1.008g/mol]

S: (1.926 /32.07) = 0.06006 mol S atoms [molar mass of S =32.07g/mol]

  1. By dividing by the smallest number, change the numbers to whole numbers.

Fe =0.03998/0.03998 = 1.000

S = 0.06006/0.03998mol = 1.502

  1. As we still have not reached a ratio that gives whole numbers in the formula we multiply by a number that will give us whole numbers

Fe: (1.000)2 = 2.000

S: (1.502)2 = 3.004

Empirical formula = Fe2S3

Er. Neeraj K.Anand is a freelance mentor and writer who specializes in Engineering & Science subjects. Neeraj Anand received a B.Tech degree in Electronics and Communication Engineering from N.I.T Warangal & M.Tech Post Graduation from IETE, New Delhi. He has over 30 years of teaching experience and serves as the Head of Department of ANAND CLASSES. He concentrated all his energy and experiences in academics and subsequently grew up as one of the best mentors in the country for students aspiring for success in competitive examinations. In parallel, he started a Technical Publication "ANAND TECHNICAL PUBLISHERS" in 2002 and Educational Newspaper "NATIONAL EDUCATION NEWS" in 2014 at Jalandhar. Now he is a Director of leading publication "ANAND TECHNICAL PUBLISHERS", "ANAND CLASSES" and "NATIONAL EDUCATION NEWS". He has published more than hundred books in the field of Physics, Mathematics, Computers and Information Technology. Besides this he has written many books to help students prepare for IIT-JEE and AIPMT entrance exams. He is an executive member of the IEEE (Institute of Electrical & Electronics Engineers. USA) and honorary member of many Indian scientific societies such as Institution of Electronics & Telecommunication Engineers, Aeronautical Society of India, Bioinformatics Institute of India, Institution of Engineers. He has got award from American Biographical Institute Board of International Research in the year 2005.